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deb-goldedplus/goldlib/myspell/affentry.cxx

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#include "license.rea"
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#include <cctype>
#include <cstring>
#include <cstdlib>
#include <cstdio>
#include "affentry.hxx"
#if !defined(_MSC_VER)
using namespace std;
#endif
extern char * mystrdup(const char * s);
extern char * myrevstrdup(const char * s);
PfxEntry::PfxEntry(AffixMgr* pmgr, affentry* dp)
{
// register affix manager
pmyMgr = pmgr;
// set up its intial values
achar = dp->achar; // char flag
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strip = dp->strip; // string to strip
appnd = dp->appnd; // string to append
stripl = dp->stripl; // length of strip string
appndl = dp->appndl; // length of append string
numconds = dp->numconds; // number of conditions to match
xpflg = dp->xpflg; // cross product flag
// then copy over all of the conditions
memcpy(&conds[0],&dp->conds[0],SETSIZE*sizeof(conds[0]));
next = NULL;
nextne = NULL;
nexteq = NULL;
}
PfxEntry::~PfxEntry()
{
achar = '\0';
if (appnd) free(appnd);
if (strip)free(strip);
pmyMgr = NULL;
appnd = NULL;
strip = NULL;
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}
// add prefix to this word assuming conditions hold
char * PfxEntry::add(const char * word, int len)
{
int cond;
char tword[MAXWORDLEN+1];
/* make sure all conditions match */
if ((len > stripl) && (len >= numconds)) {
unsigned char * cp = (unsigned char *) word;
for (cond = 0; cond < numconds; cond++) {
if ((conds[*cp++] & (1 << cond)) == 0)
break;
}
if (cond >= numconds) {
/* we have a match so add prefix */
int tlen = 0;
if (appndl) {
strcpy(tword,appnd);
tlen += appndl;
}
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char * pp = tword + tlen;
strcpy(pp, (word + stripl));
return mystrdup(tword);
}
}
return NULL;
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}
// check if this prefix entry matches
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struct hentry * PfxEntry::check(const char * word, int len)
{
int cond; // condition number being examined
int tmpl; // length of tmpword
struct hentry * he; // hash entry of root word or NULL
unsigned char * cp;
char tmpword[MAXWORDLEN+1];
// on entry prefix is 0 length or already matches the beginning of the word.
// So if the remaining root word has positive length
// and if there are enough chars in root word and added back strip chars
// to meet the number of characters conditions, then test it
tmpl = len - appndl;
if ((tmpl > 0) && (tmpl + stripl >= numconds)) {
// generate new root word by removing prefix and adding
// back any characters that would have been stripped
if (stripl) strcpy (tmpword, strip);
strcpy ((tmpword + stripl), (word + appndl));
// now make sure all of the conditions on characters
// are met. Please see the appendix at the end of
// this file for more info on exactly what is being
// tested
cp = (unsigned char *)tmpword;
for (cond = 0; cond < numconds; cond++) {
if ((conds[*cp++] & (1 << cond)) == 0) break;
}
// if all conditions are met then check if resulting
// root word in the dictionary
if (cond >= numconds) {
tmpl += stripl;
if ((he = pmyMgr->lookup(tmpword)) != NULL) {
if (TESTAFF(he->astr, achar, he->alen)) return he;
}
// prefix matched but no root word was found
// if XPRODUCT is allowed, try again but now
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// ross checked combined with a suffix
if (xpflg & XPRODUCT) {
he = pmyMgr->suffix_check(tmpword, tmpl, XPRODUCT, (AffEntry *)this);
if (he) return he;
}
}
}
return NULL;
}
SfxEntry::SfxEntry(AffixMgr * pmgr, affentry* dp)
{
// register affix manager
pmyMgr = pmgr;
// set up its intial values
achar = dp->achar; // char flag
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strip = dp->strip; // string to strip
appnd = dp->appnd; // string to append
stripl = dp->stripl; // length of strip string
appndl = dp->appndl; // length of append string
numconds = dp->numconds; // number of conditions to match
xpflg = dp->xpflg; // cross product flag
// then copy over all of the conditions
memcpy(&conds[0],&dp->conds[0],SETSIZE*sizeof(conds[0]));
rappnd = myrevstrdup(appnd);
}
SfxEntry::~SfxEntry()
{
achar = '\0';
if (appnd) free(appnd);
if (rappnd) free(rappnd);
if (strip) free(strip);
pmyMgr = NULL;
appnd = NULL;
strip = NULL;
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}
// add suffix to this word assuming conditions hold
char * SfxEntry::add(const char * word, int len)
{
int cond;
char tword[MAXWORDLEN+1];
/* make sure all conditions match */
if ((len > stripl) && (len >= numconds)) {
unsigned char * cp = (unsigned char *) (word + len);
for (cond = numconds; --cond >=0; ) {
if ((conds[*--cp] & (1 << cond)) == 0)
break;
}
if (cond < 0) {
/* we have a match so add suffix */
strcpy(tword,word);
int tlen = len;
if (stripl) {
tlen -= stripl;
}
char * pp = (tword + tlen);
if (appndl) {
strcpy(pp,appnd);
tlen += appndl;
} else *pp = '\0';
return mystrdup(tword);
}
}
return NULL;
}
// see if this suffix is present in the word
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struct hentry * SfxEntry::check(const char * word, int len, int optflags, AffEntry* ppfx)
{
int tmpl; // length of tmpword
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int cond; // condition beng examined
struct hentry * he; // hash entry pointer
unsigned char * cp;
char tmpword[MAXWORDLEN+1];
PfxEntry* ep = (PfxEntry *) ppfx;
// if this suffix is being cross checked with a prefix
// but it does not support cross products skip it
if ((optflags & XPRODUCT) != 0 && (xpflg & XPRODUCT) == 0)
return NULL;
// upon entry suffix is 0 length or already matches the end of the word.
// So if the remaining root word has positive length
// and if there are enough chars in root word and added back strip chars
// to meet the number of characters conditions, then test it
tmpl = len - appndl;
if ((tmpl > 0) && (tmpl + stripl >= numconds)) {
// generate new root word by removing suffix and adding
// back any characters that would have been stripped or
// or null terminating the shorter string
strcpy (tmpword, word);
cp = (unsigned char *)(tmpword + tmpl);
if (stripl) {
strcpy ((char *)cp, strip);
tmpl += stripl;
cp = (unsigned char *)(tmpword + tmpl);
} else *cp = '\0';
// now make sure all of the conditions on characters
// are met. Please see the appendix at the end of
// this file for more info on exactly what is being
// tested
for (cond = numconds; --cond >= 0; ) {
if ((conds[*--cp] & (1 << cond)) == 0) break;
}
// if all conditions are met then check if resulting
// root word in the dictionary
if (cond < 0) {
if ((he = pmyMgr->lookup(tmpword)) != NULL) {
if (TESTAFF(he->astr, achar , he->alen) &&
((optflags & XPRODUCT) == 0 ||
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TESTAFF(he->astr, ep->getFlag(), he->alen))) return he;
}
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}
}
return NULL;
}
#if 0
Appendix: Understanding Affix Code
An affix is either a prefix or a suffix attached to root words to make
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other words.
Basically a Prefix or a Suffix is set of AffEntry objects
which store information about the prefix or suffix along
with supporting routines to check if a word has a particular
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prefix or suffix or a combination.
The structure affentry is defined as follows:
struct affentry
{
unsigned char achar; // char used to represent the affix
char * strip; // string to strip before adding affix
char * appnd; // the affix string to add
short stripl; // length of the strip string
short appndl; // length of the affix string
short numconds; // the number of conditions that must be met
short xpflg; // flag: XPRODUCT- combine both prefix and suffix
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char conds[SETSIZE]; // array which encodes the conditions to be met
};
Here is a suffix borrowed from the en_US.aff file. This file
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is whitespace delimited.
SFX D Y 4
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SFX D 0 e d
SFX D y ied [^aeiou]y
SFX D 0 ed [^ey]
SFX D 0 ed [aeiou]y
This information can be interpreted as follows:
In the first line has 4 fields
Field
-----
1 SFX - indicates this is a suffix
2 D - is the name of the character flag which represents this suffix
3 Y - indicates it can be combined with prefixes (cross product)
4 4 - indicates that sequence of 4 affentry structures are needed to
properly store the affix information
The remaining lines describe the unique information for the 4 SfxEntry
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objects that make up this affix. Each line can be interpreted
as follows: (note fields 1 and 2 are as a check against line 1 info)
Field
-----
1 SFX - indicates this is a suffix
2 D - is the name of the character flag for this affix
3 y - the string of chars to strip off before adding affix
(a 0 here indicates the NULL string)
4 ied - the string of affix characters to add
5 [^aeiou]y - the conditions which must be met before the affix
can be applied
Field 5 is interesting. Since this is a suffix, field 5 tells us that
there are 2 conditions that must be met. The first condition is that
the next to the last character in the word must *NOT* be any of the
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following "a", "e", "i", "o" or "u". The second condition is that
the last character of the word must end in "y".
So how can we encode this information concisely and be able to
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test for both conditions in a fast manner? The answer is found
but studying the wonderful ispell code of Geoff Kuenning, et.al.
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(now available under a normal BSD license).
If we set up a conds array of 256 bytes indexed (0 to 255) and access it
using a character (cast to an unsigned char) of a string, we have 8 bits
of information we can store about that character. Specifically we
could use each bit to say if that character is allowed in any of the
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last (or first for prefixes) 8 characters of the word.
Basically, each character at one end of the word (up to the number
of conditions) is used to index into the conds array and the resulting
value found there says whether the that character is valid for a
specific character position in the word.
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For prefixes, it does this by setting bit 0 if that char is valid
in the first position, bit 1 if valid in the second position, and so on.
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If a bit is not set, then that char is not valid for that postion in the
word.
If working with suffixes bit 0 is used for the character closest
to the front, bit 1 for the next character towards the end, ...,
with bit numconds-1 representing the last char at the end of the string.
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Note: since entries in the conds[] are 8 bits, only 8 conditions
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(read that only 8 character positions) can be examined at one
end of a word (the beginning for prefixes and the end for suffixes.
So to make this clearer, lets encode the conds array values for the
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first two affentries for the suffix D described earlier.
For the first affentry:
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numconds = 1 (only examine the last character)
conds['e'] = (1 << 0) (the word must end in an E)
all others are all 0
For the second affentry:
numconds = 2 (only examine the last two characters)
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conds[X] = conds[X] | (1 << 0) (aeiou are not allowed)
where X is all characters *but* a, e, i, o, or u
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conds['y'] = (1 << 1) (the last char must be a y)
all other bits for all other entries in the conds array are zero
#endif